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14021540441 = 67209276723
BaseRepresentation
bin11010000111011111…
…11011101001011001
31100012012000001111122
431003233323221121
5212204003243231
610235202135025
71004316061436
oct150357735131
940165001448
1014021540441
115a45880957
122873951475
131425c114bc
149702c2b8d
15570e8a77b
hex343bfba59

14021540441 has 4 divisors (see below), whose sum is σ = 14230817232. Its totient is φ = 13812263652.

The previous prime is 14021540419. The next prime is 14021540453. The reversal of 14021540441 is 14404512041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14021540441 - 214 = 14021524057 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14021540441.

It is not an unprimeable number, because it can be changed into a prime (14021530441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 104638295 + ... + 104638428.

It is an arithmetic number, because the mean of its divisors is an integer number (3557704308).

Almost surely, 214021540441 is an apocalyptic number.

It is an amenable number.

14021540441 is a deficient number, since it is larger than the sum of its proper divisors (209276791).

14021540441 is an equidigital number, since it uses as much as digits as its factorization.

14021540441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 209276790.

The product of its (nonzero) digits is 2560, while the sum is 26.

The spelling of 14021540441 in words is "fourteen billion, twenty-one million, five hundred forty thousand, four hundred forty-one".

Divisors: 1 67 209276723 14021540441