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1402201311073 is a prime number
BaseRepresentation
bin10100011001111001101…
…101100000011101100001
311222001022211010222120121
4110121321231200131201
5140433202013423243
62552055024240241
7203206566326413
oct24317155403541
94861284128517
101402201311073
114a07410a2942
121a790a470081
13a22c49a71c4
144bc1cb089b3
152671b53a1ed
hex14679b60761

1402201311073 has 2 divisors, whose sum is σ = 1402201311074. Its totient is φ = 1402201311072.

The previous prime is 1402201311061. The next prime is 1402201311089. The reversal of 1402201311073 is 3701131022041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 735011299584 + 667190011489 = 857328^2 + 816817^2 .

It is a cyclic number.

It is not a de Polignac number, because 1402201311073 - 213 = 1402201302881 is a prime.

It is a super-2 number, since 2×14022013110732 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1402201311473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701100655536 + 701100655537.

It is an arithmetic number, because the mean of its divisors is an integer number (701100655537).

Almost surely, 21402201311073 is an apocalyptic number.

It is an amenable number.

1402201311073 is a deficient number, since it is larger than the sum of its proper divisors (1).

1402201311073 is an equidigital number, since it uses as much as digits as its factorization.

1402201311073 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 25.

The spelling of 1402201311073 in words is "one trillion, four hundred two billion, two hundred one million, three hundred eleven thousand, seventy-three".