Base | Representation |
---|---|
bin | 11111111000011110001111… |
… | …111100001001010011000011 |
3 | 200101110220212200101102222221 |
4 | 133320132033330021103003 |
5 | 121334331443312033443 |
6 | 1214120135355111511 |
7 | 41351401401214336 |
oct | 3770361774112303 |
9 | 611426780342887 |
10 | 140220212221123 |
11 | 407510702a1321 |
12 | 13887749442597 |
13 | 603192b380318 |
14 | 268a9a193861d |
15 | 11326b214beed |
hex | 7f878ff094c3 |
140220212221123 has 2 divisors, whose sum is σ = 140220212221124. Its totient is φ = 140220212221122.
The previous prime is 140220212221097. The next prime is 140220212221157. The reversal of 140220212221123 is 321122212022041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 140220212221123 - 25 = 140220212221091 is a prime.
It is a super-2 number, since 2×1402202122211232 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (140220212921123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70110106110561 + 70110106110562.
It is an arithmetic number, because the mean of its divisors is an integer number (70110106110562).
Almost surely, 2140220212221123 is an apocalyptic number.
140220212221123 is a deficient number, since it is larger than the sum of its proper divisors (1).
140220212221123 is an equidigital number, since it uses as much as digits as its factorization.
140220212221123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 140220212221123 its reverse (321122212022041), we get a palindrome (461342424243164).
The spelling of 140220212221123 in words is "one hundred forty trillion, two hundred twenty billion, two hundred twelve million, two hundred twenty-one thousand, one hundred twenty-three".
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