Base | Representation |
---|---|
bin | 11111111000011110011011… |
… | …011000111101000010000001 |
3 | 200101110221101001212012110021 |
4 | 133320132123120331002001 |
5 | 121334332342001304213 |
6 | 1214120210420333441 |
7 | 41351406223103431 |
oct | 3770363330750201 |
9 | 611427331765407 |
10 | 140220404322433 |
11 | 40751159779936 |
12 | 138877a1844281 |
13 | 603195c100336 |
14 | 268a9bd2622c1 |
15 | 11326c3e45d8d |
hex | 7f879b63d081 |
140220404322433 has 2 divisors, whose sum is σ = 140220404322434. Its totient is φ = 140220404322432.
The previous prime is 140220404322421. The next prime is 140220404322541. The reversal of 140220404322433 is 334223404022041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 77959593457729 + 62260810864704 = 8829473^2 + 7890552^2 .
It is a cyclic number.
It is not a de Polignac number, because 140220404322433 - 213 = 140220404314241 is a prime.
It is not a weakly prime, because it can be changed into another prime (140220404322233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70110202161216 + 70110202161217.
It is an arithmetic number, because the mean of its divisors is an integer number (70110202161217).
Almost surely, 2140220404322433 is an apocalyptic number.
It is an amenable number.
140220404322433 is a deficient number, since it is larger than the sum of its proper divisors (1).
140220404322433 is an equidigital number, since it uses as much as digits as its factorization.
140220404322433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 110592, while the sum is 34.
Adding to 140220404322433 its reverse (334223404022041), we get a palindrome (474443808344474).
The spelling of 140220404322433 in words is "one hundred forty trillion, two hundred twenty billion, four hundred four million, three hundred twenty-two thousand, four hundred thirty-three".
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