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14022040444411 is a prime number
BaseRepresentation
bin1100110000001100001010…
…1111010101110111111011
31211122111100002220112112111
43030003002233111313323
53314214114323210121
645453345250153151
72645026143135016
oct314030257256773
954574302815474
1014022040444411
1145167943057aa
1216a5694b827b7
137a9371296b2c
1436695573a37d
15194b2ad6a2e1
hexcc0c2bd5dfb

14022040444411 has 2 divisors, whose sum is σ = 14022040444412. Its totient is φ = 14022040444410.

The previous prime is 14022040444403. The next prime is 14022040444453. The reversal of 14022040444411 is 11444404022041.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14022040444411 - 23 = 14022040444403 is a prime.

It is a super-2 number, since 2×140220404444112 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14022040447411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7011020222205 + 7011020222206.

It is an arithmetic number, because the mean of its divisors is an integer number (7011020222206).

Almost surely, 214022040444411 is an apocalyptic number.

14022040444411 is a deficient number, since it is larger than the sum of its proper divisors (1).

14022040444411 is an equidigital number, since it uses as much as digits as its factorization.

14022040444411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16384, while the sum is 31.

Adding to 14022040444411 its reverse (11444404022041), we get a palindrome (25466444466452).

The spelling of 14022040444411 in words is "fourteen trillion, twenty-two billion, forty million, four hundred forty-four thousand, four hundred eleven".