140220421120433 has 4 divisors (see below), whose sum is σ = 140287224562800. Its totient is φ = 140153617678068.

The previous prime is 140220421120387. The next prime is 140220421120519. The reversal of 140220421120433 is 334021124022041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140220421120433 - 2¹⁰ = 140220421119409 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140220421120396 and 140220421120405.

It is not an unprimeable number, because it can be changed into a prime (140220426120433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33401718035 + ... + 33401722232.

It is an arithmetic number, because the mean of its divisors is an integer number (35071806140700).

Almost surely, 2^{140220421120433} is an apocalyptic number.

It is an amenable number.

140220421120433 is a deficient number, since it is larger than the sum of its proper divisors (66803442367).

140220421120433 is an equidigital number, since it uses as much as digits as its factorization.

140220421120433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66803442366.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 140220421120433 its reverse (334021124022041), we get a palindrome (474241545142474).

The spelling of 140220421120433 in words is "one hundred forty trillion, two hundred twenty billion, four hundred twenty-one million, one hundred twenty thousand, four hundred thirty-three".