14022101040433 has 4 divisors (see below), whose sum is σ = 14022443894848. Its totient is φ = 14021758186020.

The previous prime is 14022101040349. The next prime is 14022101040487. The reversal of 14022101040433 is 33404010122041.

14022101040433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14022101040433 is a prime.

It is a super-2 number, since 2×14022101040433² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14022101040398 and 14022101040407.

It is not an unprimeable number, because it can be changed into a prime (14022101046433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 171365853 + ... + 171447658.

It is an arithmetic number, because the mean of its divisors is an integer number (3505610973712).

Almost surely, 2^{14022101040433} is an apocalyptic number.

It is an amenable number.

14022101040433 is a deficient number, since it is larger than the sum of its proper divisors (342854415).

14022101040433 is an equidigital number, since it uses as much as digits as its factorization.

14022101040433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 342854414.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14022101040433 its reverse (33404010122041), we get a palindrome (47426111162474).

The spelling of 14022101040433 in words is "fourteen trillion, twenty-two billion, one hundred one million, forty thousand, four hundred thirty-three".