Base | Representation |
---|---|
bin | 1100110000001101001110… |
… | …1001111100111110110011 |
3 | 1211122112001212221001221022 |
4 | 3030003103221330332303 |
5 | 3314220210001310103 |
6 | 45453433345050055 |
7 | 2645036160323156 |
oct | 314032351747663 |
9 | 54575055831838 |
10 | 14022324244403 |
11 | 451691a524952 |
12 | 16a575402692b |
13 | 7a93b8012017 |
14 | 3669812d3c9d |
15 | 194b45c29138 |
hex | cc0d3a7cfb3 |
14022324244403 has 8 divisors (see below), whose sum is σ = 14563394818560. Its totient is φ = 13491367139080.
The previous prime is 14022324244391. The next prime is 14022324244549. The reversal of 14022324244403 is 30444242322041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14022324244403 - 224 = 14022307467187 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14025324244403) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2528364383 + ... + 2528369928.
It is an arithmetic number, because the mean of its divisors is an integer number (1820424352320).
Almost surely, 214022324244403 is an apocalyptic number.
14022324244403 is a deficient number, since it is larger than the sum of its proper divisors (541070574157).
14022324244403 is an equidigital number, since it uses as much as digits as its factorization.
14022324244403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5056734417.
The product of its (nonzero) digits is 147456, while the sum is 35.
Adding to 14022324244403 its reverse (30444242322041), we get a palindrome (44466566566444).
The spelling of 14022324244403 in words is "fourteen trillion, twenty-two billion, three hundred twenty-four million, two hundred forty-four thousand, four hundred three".
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