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140223404310001 is a prime number
BaseRepresentation
bin11111111000100001001110…
…001100111111110111110001
3200101111020010010212100201221
4133320201032030333313301
5121334410013000410001
61214121424224425041
741351543451425035
oct3770411614776761
9611436103770657
10140223404310001
1140752459130a01
121388829a478181
1360320197abccc
14268abc58641c5
1511327ec4d61a1
hex7f884e33fdf1

140223404310001 has 2 divisors, whose sum is σ = 140223404310002. Its totient is φ = 140223404310000.

The previous prime is 140223404309969. The next prime is 140223404310013. The reversal of 140223404310001 is 100013404322041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130418684010000 + 9804720300001 = 11420100^2 + 3131249^2 .

It is a cyclic number.

It is not a de Polignac number, because 140223404310001 - 25 = 140223404309969 is a prime.

It is not a weakly prime, because it can be changed into another prime (140223404310091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70111702155000 + 70111702155001.

It is an arithmetic number, because the mean of its divisors is an integer number (70111702155001).

Almost surely, 2140223404310001 is an apocalyptic number.

It is an amenable number.

140223404310001 is a deficient number, since it is larger than the sum of its proper divisors (1).

140223404310001 is an equidigital number, since it uses as much as digits as its factorization.

140223404310001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 140223404310001 its reverse (100013404322041), we get a palindrome (240236808632042).

The spelling of 140223404310001 in words is "one hundred forty trillion, two hundred twenty-three billion, four hundred four million, three hundred ten thousand, one".