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140223431444513 is a prime number
BaseRepresentation
bin11111111000100001001111…
…110100100000100000100001
3200101111020012000220221021212
4133320201033310200200201
5121334410041422211023
61214121431034155505
741351544231160304
oct3770411764404041
9611436160827255
10140223431444513
114075247248451a
12138882a7582b95
1360320222bc931
14268abc92c8b3b
1511327eea95e78
hex7f884fd20821

140223431444513 has 2 divisors, whose sum is σ = 140223431444514. Its totient is φ = 140223431444512.

The previous prime is 140223431444387. The next prime is 140223431444527. The reversal of 140223431444513 is 315444134322041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 140111917524544 + 111513919969 = 11836888^2 + 333937^2 .

It is a cyclic number.

It is not a de Polignac number, because 140223431444513 - 218 = 140223431182369 is a prime.

It is a super-2 number, since 2×1402234314445132 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (140223431444563) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70111715722256 + 70111715722257.

It is an arithmetic number, because the mean of its divisors is an integer number (70111715722257).

Almost surely, 2140223431444513 is an apocalyptic number.

It is an amenable number.

140223431444513 is a deficient number, since it is larger than the sum of its proper divisors (1).

140223431444513 is an equidigital number, since it uses as much as digits as its factorization.

140223431444513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 552960, while the sum is 41.

Adding to 140223431444513 its reverse (315444134322041), we get a palindrome (455667565766554).

The spelling of 140223431444513 in words is "one hundred forty trillion, two hundred twenty-three billion, four hundred thirty-one million, four hundred forty-four thousand, five hundred thirteen".