140224012134131 has 2 divisors, whose sum is σ = 140224012134132. Its totient is φ = 140224012134130.

The previous prime is 140224012134113. The next prime is 140224012134191. The reversal of 140224012134131 is 131431210422041.

Together with previous prime (140224012134113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140224012134131 is a prime.

It is a super-2 number, since 2×140224012134131² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140224012134094 and 140224012134103.

It is not a weakly prime, because it can be changed into another prime (140224012134191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70112006067065 + 70112006067066.

It is an arithmetic number, because the mean of its divisors is an integer number (70112006067066).

Almost surely, 2^{140224012134131} is an apocalyptic number.

140224012134131 is a deficient number, since it is larger than the sum of its proper divisors (1).

140224012134131 is an equidigital number, since it uses as much as digits as its factorization.

140224012134131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 140224012134131 its reverse (131431210422041), we get a palindrome (271655222556172).

The spelling of 140224012134131 in words is "one hundred forty trillion, two hundred twenty-four billion, twelve million, one hundred thirty-four thousand, one hundred thirty-one".