Base | Representation |
---|---|
bin | 1000001010011001100… |
… | …0010001001011011011 |
3 | 111101221220010000102111 |
4 | 2002212120101023123 |
5 | 4244142431130042 |
6 | 144230530413151 |
7 | 13063016110342 |
oct | 2024630211333 |
9 | 441856100374 |
10 | 140230333147 |
11 | 54520404913 |
12 | 23216a311b7 |
13 | 102ba509ab8 |
14 | 6b04068b59 |
15 | 39ab06d517 |
hex | 20a66112db |
140230333147 has 2 divisors, whose sum is σ = 140230333148. Its totient is φ = 140230333146.
The previous prime is 140230333121. The next prime is 140230333151. The reversal of 140230333147 is 741333032041.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140230333147 is a prime.
It is not a weakly prime, because it can be changed into another prime (140230333447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70115166573 + 70115166574.
It is an arithmetic number, because the mean of its divisors is an integer number (70115166574).
Almost surely, 2140230333147 is an apocalyptic number.
140230333147 is a deficient number, since it is larger than the sum of its proper divisors (1).
140230333147 is an equidigital number, since it uses as much as digits as its factorization.
140230333147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 31.
Adding to 140230333147 its reverse (741333032041), we get a palindrome (881563365188).
The spelling of 140230333147 in words is "one hundred forty billion, two hundred thirty million, three hundred thirty-three thousand, one hundred forty-seven".
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