140231400433 has 2 divisors, whose sum is σ = 140231400434. Its totient is φ = 140231400432.

The previous prime is 140231400403. The next prime is 140231400461. The reversal of 140231400433 is 334004132041.

140231400433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117753295104 + 22478105329 = 343152^2 + 149927^2 .

It is a cyclic number.

It is not a de Polignac number, because 140231400433 - 2⁵ = 140231400401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 140231400398 and 140231400407.

It is not a weakly prime, because it can be changed into another prime (140231400403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70115700216 + 70115700217.

It is an arithmetic number, because the mean of its divisors is an integer number (70115700217).

Almost surely, 2^140231400433 is an apocalyptic number.

It is an amenable number.

140231400433 is a deficient number, since it is larger than the sum of its proper divisors (1).

140231400433 is an equidigital number, since it uses as much as digits as its factorization.

140231400433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 140231400433 its reverse (334004132041), we get a palindrome (474235532474).

The spelling of 140231400433 in words is "one hundred forty billion, two hundred thirty-one million, four hundred thousand, four hundred thirty-three".