Search a number
-
+
1402329995281 is a prime number
BaseRepresentation
bin10100011010000001011…
…000011001100000010001
311222001122210021211010101
4110122001120121200101
5140433432434322111
62552115502332401
7203213021200135
oct24320130314021
94861583254111
101402329995281
114a07a77a6226
121a794558a101
13a2315551ac7
144bc31c453c5
15267279a8bc1
hex14681619811

1402329995281 has 2 divisors, whose sum is σ = 1402329995282. Its totient is φ = 1402329995280.

The previous prime is 1402329995267. The next prime is 1402329995327. The reversal of 1402329995281 is 1825999232041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1298414670400 + 103915324881 = 1139480^2 + 322359^2 .

It is a cyclic number.

It is not a de Polignac number, because 1402329995281 - 25 = 1402329995249 is a prime.

It is a super-2 number, since 2×14023299952812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1402329995201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701164997640 + 701164997641.

It is an arithmetic number, because the mean of its divisors is an integer number (701164997641).

Almost surely, 21402329995281 is an apocalyptic number.

It is an amenable number.

1402329995281 is a deficient number, since it is larger than the sum of its proper divisors (1).

1402329995281 is an equidigital number, since it uses as much as digits as its factorization.

1402329995281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2799360, while the sum is 55.

The spelling of 1402329995281 in words is "one trillion, four hundred two billion, three hundred twenty-nine million, nine hundred ninety-five thousand, two hundred eighty-one".