140233210012433 has 2 divisors, whose sum is σ = 140233210012434. Its totient is φ = 140233210012432.

The previous prime is 140233210012403. The next prime is 140233210012451. The reversal of 140233210012433 is 334210012332041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90590363302609 + 49642846709824 = 9517897^2 + 7045768^2 .

It is a cyclic number.

It is not a de Polignac number, because 140233210012433 - 2¹⁰ = 140233210011409 is a prime.

It is a super-2 number, since 2×140233210012433² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140233210012396 and 140233210012405.

It is not a weakly prime, because it can be changed into another prime (140233210012403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70116605006216 + 70116605006217.

It is an arithmetic number, because the mean of its divisors is an integer number (70116605006217).

Almost surely, 2^{140233210012433} is an apocalyptic number.

It is an amenable number.

140233210012433 is a deficient number, since it is larger than the sum of its proper divisors (1).

140233210012433 is an equidigital number, since it uses as much as digits as its factorization.

140233210012433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 140233210012433 its reverse (334210012332041), we get a palindrome (474443222344474).

The spelling of 140233210012433 in words is "one hundred forty trillion, two hundred thirty-three billion, two hundred ten million, twelve thousand, four hundred thirty-three".