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14023323243473 is a prime number
BaseRepresentation
bin1100110000010000111100…
…1100110101001111010001
31211122121122111201111000212
43030010033030311033101
53314224231222242343
645454120433053505
72645103010554665
oct314041714651721
954577574644025
1014023323243473
114517292424715
1216a59926b7295
137a9516c8b72b
14366a37c608a5
15194ba37adc18
hexcc10f3353d1

14023323243473 has 2 divisors, whose sum is σ = 14023323243474. Its totient is φ = 14023323243472.

The previous prime is 14023323243421. The next prime is 14023323243499. The reversal of 14023323243473 is 37434232332041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11830930710544 + 2192392532929 = 3439612^2 + 1480673^2 .

It is a cyclic number.

It is not a de Polignac number, because 14023323243473 - 210 = 14023323242449 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14023323243473.

It is not a weakly prime, because it can be changed into another prime (14023323243373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7011661621736 + 7011661621737.

It is an arithmetic number, because the mean of its divisors is an integer number (7011661621737).

Almost surely, 214023323243473 is an apocalyptic number.

It is an amenable number.

14023323243473 is a deficient number, since it is larger than the sum of its proper divisors (1).

14023323243473 is an equidigital number, since it uses as much as digits as its factorization.

14023323243473 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 870912, while the sum is 41.

The spelling of 14023323243473 in words is "fourteen trillion, twenty-three billion, three hundred twenty-three million, two hundred forty-three thousand, four hundred seventy-three".