140233511731 has 2 divisors, whose sum is σ = 140233511732. Its totient is φ = 140233511730.

The previous prime is 140233511701. The next prime is 140233511741. The reversal of 140233511731 is 137115332041.

It is a strong prime.

It is an emirp because it is prime and its reverse (137115332041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140233511731 - 2⁵ = 140233511699 is a prime.

It is a super-2 number, since 2×140233511731² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140233511693 and 140233511702.

It is not a weakly prime, because it can be changed into another prime (140233511701) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70116755865 + 70116755866.

It is an arithmetic number, because the mean of its divisors is an integer number (70116755866).

Almost surely, 2^140233511731 is an apocalyptic number.

140233511731 is a deficient number, since it is larger than the sum of its proper divisors (1).

140233511731 is an equidigital number, since it uses as much as digits as its factorization.

140233511731 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7560, while the sum is 31.

Adding to 140233511731 its reverse (137115332041), we get a palindrome (277348843772).

The spelling of 140233511731 in words is "one hundred forty billion, two hundred thirty-three million, five hundred eleven thousand, seven hundred thirty-one".