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140234001041041 is a prime number
BaseRepresentation
bin11111111000101011000101…
…110100010100011010010001
3200101112020110122111001221221
4133320223011310110122101
5121340043213231303131
61214130335525245041
741352400163232445
oct3770530564243221
9611466418431857
10140234001041041
11407569a6770866
121388a357263781
136033017cbc16b
14268b50cd5c825
151132c1c968411
hex7f8ac5d14691

140234001041041 has 2 divisors, whose sum is σ = 140234001041042. Its totient is φ = 140234001041040.

The previous prime is 140234001040949. The next prime is 140234001041053. The reversal of 140234001041041 is 140140100432041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 137296876890625 + 2937124150416 = 11717375^2 + 1713804^2 .

It is a cyclic number.

It is not a de Polignac number, because 140234001041041 - 215 = 140234001008273 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 140234001040997 and 140234001041015.

It is not a weakly prime, because it can be changed into another prime (140234001041341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70117000520520 + 70117000520521.

It is an arithmetic number, because the mean of its divisors is an integer number (70117000520521).

Almost surely, 2140234001041041 is an apocalyptic number.

It is an amenable number.

140234001041041 is a deficient number, since it is larger than the sum of its proper divisors (1).

140234001041041 is an equidigital number, since it uses as much as digits as its factorization.

140234001041041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 140234001041041 its reverse (140140100432041), we get a palindrome (280374101473082).

The spelling of 140234001041041 in words is "one hundred forty trillion, two hundred thirty-four billion, one million, forty-one thousand, forty-one".