140240032022131 has 4 divisors (see below), whose sum is σ = 140467325429592. Its totient is φ = 140012738614672.

The previous prime is 140240032022113. The next prime is 140240032022141. The reversal of 140240032022131 is 131220230042041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140240032022131 - 2¹⁷ = 140240031891059 is a prime.

It is a super-2 number, since 2×140240032022131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140240032022096 and 140240032022105.

It is not an unprimeable number, because it can be changed into a prime (140240032022141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113646702805 + ... + 113646704038.

It is an arithmetic number, because the mean of its divisors is an integer number (35116831357398).

Almost surely, 2^{140240032022131} is an apocalyptic number.

140240032022131 is a deficient number, since it is larger than the sum of its proper divisors (227293407461).

140240032022131 is an equidigital number, since it uses as much as digits as its factorization.

140240032022131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 227293407460.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 140240032022131 its reverse (131220230042041), we get a palindrome (271460262064172).

The spelling of 140240032022131 in words is "one hundred forty trillion, two hundred forty billion, thirty-two million, twenty-two thousand, one hundred thirty-one".