Base | Representation |
---|---|
bin | 1100110000010011100011… |
… | …0111101001101100100011 |
3 | 1211122200110020011222021121 |
4 | 3030010320313221230203 |
5 | 3314232144204143433 |
6 | 45454314045033111 |
7 | 2645126230001335 |
oct | 314047067515443 |
9 | 54580406158247 |
10 | 14024022334243 |
11 | 4517611002989 |
12 | 16a5b48855797 |
13 | 7a95c8a6cccc |
14 | 366aa2a3d455 |
15 | 194be4d51c2d |
hex | cc138de9b23 |
14024022334243 has 2 divisors, whose sum is σ = 14024022334244. Its totient is φ = 14024022334242.
The previous prime is 14024022334207. The next prime is 14024022334253. The reversal of 14024022334243 is 34243322042041.
14024022334243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14024022334243 - 217 = 14024022203171 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14024022334199 and 14024022334208.
It is not a weakly prime, because it can be changed into another prime (14024022334253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7012011167121 + 7012011167122.
It is an arithmetic number, because the mean of its divisors is an integer number (7012011167122).
Almost surely, 214024022334243 is an apocalyptic number.
14024022334243 is a deficient number, since it is larger than the sum of its proper divisors (1).
14024022334243 is an equidigital number, since it uses as much as digits as its factorization.
14024022334243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 110592, while the sum is 34.
Adding to 14024022334243 its reverse (34243322042041), we get a palindrome (48267344376284).
The spelling of 14024022334243 in words is "fourteen trillion, twenty-four billion, twenty-two million, three hundred thirty-four thousand, two hundred forty-three".
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