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140241343153 = 281499079513
BaseRepresentation
bin1000001010011100001…
…0010001001010110001
3111101222122211101022111
42002213002101022301
54244203240440103
6144232002405321
713063211514442
oct2024702211261
9441878741274
10140241343153
115452664489a
122321a660841
13102bc8932b2
146b056d32c9
1539abee586d
hex20a70912b1

140241343153 has 4 divisors (see below), whose sum is σ = 140740422948. Its totient is φ = 139742263360.

The previous prime is 140241343139. The next prime is 140241343271. The reversal of 140241343153 is 351343142041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 88599689649 + 51641653504 = 297657^2 + 227248^2 .

It is a cyclic number.

It is not a de Polignac number, because 140241343153 - 217 = 140241212081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140241343133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 249539476 + ... + 249540037.

It is an arithmetic number, because the mean of its divisors is an integer number (35185105737).

Almost surely, 2140241343153 is an apocalyptic number.

It is an amenable number.

140241343153 is a deficient number, since it is larger than the sum of its proper divisors (499079795).

140241343153 is an equidigital number, since it uses as much as digits as its factorization.

140241343153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 499079794.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 140241343153 its reverse (351343142041), we get a palindrome (491584485194).

The spelling of 140241343153 in words is "one hundred forty billion, two hundred forty-one million, three hundred forty-three thousand, one hundred fifty-three".

Divisors: 1 281 499079513 140241343153