Base | Representation |
---|---|
bin | 11111111000110001111111… |
… | …000010000101110010001011 |
3 | 200101112221120112100001010220 |
4 | 133320301333002011302023 |
5 | 121340203343232402103 |
6 | 1214134002235441123 |
7 | 41353051466253021 |
oct | 3770617702056213 |
9 | 611487515301126 |
10 | 140241403403403 |
11 | 4075a055154205 |
12 | 1388b8822b61a3 |
13 | 6033927782a33 |
14 | 268ba120d6711 |
15 | 1133002760c53 |
hex | 7f8c7f085c8b |
140241403403403 has 4 divisors (see below), whose sum is σ = 186988537871208. Its totient is φ = 93494268935600.
The previous prime is 140241403403393. The next prime is 140241403403417. The reversal of 140241403403403 is 304304304142041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 140241403403403 - 217 = 140241403272331 is a prime.
It is not an unprimeable number, because it can be changed into a prime (140241403403503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23373567233898 + ... + 23373567233903.
It is an arithmetic number, because the mean of its divisors is an integer number (46747134467802).
Almost surely, 2140241403403403 is an apocalyptic number.
140241403403403 is a deficient number, since it is larger than the sum of its proper divisors (46747134467805).
140241403403403 is an equidigital number, since it uses as much as digits as its factorization.
140241403403403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46747134467804.
The product of its (nonzero) digits is 55296, while the sum is 33.
Adding to 140241403403403 its reverse (304304304142041), we get a palindrome (444545707545444).
The spelling of 140241403403403 in words is "one hundred forty trillion, two hundred forty-one billion, four hundred three million, four hundred three thousand, four hundred three".
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