1402433012041 has 4 divisors (see below), whose sum is σ = 1402450079184. Its totient is φ = 1402415944900.

The previous prime is 1402433011997. The next prime is 1402433012047. The reversal of 1402433012041 is 1402103342041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1402433012041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1402433011997 and 1402433012015.

It is not an unprimeable number, because it can be changed into a prime (1402433012047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8409715 + ... + 8574856.

It is an arithmetic number, because the mean of its divisors is an integer number (350612519796).

Almost surely, 2^{1402433012041} is an apocalyptic number.

It is an amenable number.

1402433012041 is a deficient number, since it is larger than the sum of its proper divisors (17067143).

1402433012041 is an equidigital number, since it uses as much as digits as its factorization.

1402433012041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17067142.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1402433012041 its reverse (1402103342041), we get a palindrome (2804536354082).

The spelling of 1402433012041 in words is "one trillion, four hundred two billion, four hundred thirty-three million, twelve thousand, forty-one".