Search a number
-
+
140243312401219 is a prime number
BaseRepresentation
bin11111111000110011110000…
…110100010101101101000011
3200101120010111120110011211201
4133320303300310111231003
5121340221300433314334
61214134515512122031
741353150006416226
oct3770636064255503
9611503446404751
10140243312401219
114075a944795555
1213890115696317
136033b70116c41
14268bb538635bd
1511330b5149c14
hex7f8cf0d15b43

140243312401219 has 2 divisors, whose sum is σ = 140243312401220. Its totient is φ = 140243312401218.

The previous prime is 140243312401163. The next prime is 140243312401249. The reversal of 140243312401219 is 912104213342041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 140243312401219 - 237 = 140105873447747 is a prime.

It is a super-2 number, since 2×1402433124012192 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (140243312401249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70121656200609 + 70121656200610.

It is an arithmetic number, because the mean of its divisors is an integer number (70121656200610).

Almost surely, 2140243312401219 is an apocalyptic number.

140243312401219 is a deficient number, since it is larger than the sum of its proper divisors (1).

140243312401219 is an equidigital number, since it uses as much as digits as its factorization.

140243312401219 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 37.

The spelling of 140243312401219 in words is "one hundred forty trillion, two hundred forty-three billion, three hundred twelve million, four hundred one thousand, two hundred nineteen".