Base | Representation |
---|---|
bin | 11111111000110011110001… |
… | …110111100000110011000011 |
3 | 200101120010112210120210222011 |
4 | 133320303301313200303003 |
5 | 121340221314440312212 |
6 | 1214134521341353351 |
7 | 41353150312166536 |
oct | 3770636167406303 |
9 | 611503483523864 |
10 | 140243330010307 |
11 | 4075a953722517 |
12 | 1389011b568857 |
13 | 6033b73971014 |
14 | 268bb55d28a1d |
15 | 11330b69774a7 |
hex | 7f8cf1de0cc3 |
140243330010307 has 2 divisors, whose sum is σ = 140243330010308. Its totient is φ = 140243330010306.
The previous prime is 140243330010253. The next prime is 140243330010341. The reversal of 140243330010307 is 703010033342041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140243330010307 - 231 = 140241182526659 is a prime.
It is a super-2 number, since 2×1402433300103072 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (140243330010607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70121665005153 + 70121665005154.
It is an arithmetic number, because the mean of its divisors is an integer number (70121665005154).
Almost surely, 2140243330010307 is an apocalyptic number.
140243330010307 is a deficient number, since it is larger than the sum of its proper divisors (1).
140243330010307 is an equidigital number, since it uses as much as digits as its factorization.
140243330010307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 31.
Adding to 140243330010307 its reverse (703010033342041), we get a palindrome (843253363352348).
The spelling of 140243330010307 in words is "one hundred forty trillion, two hundred forty-three billion, three hundred thirty million, ten thousand, three hundred seven".
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