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14024340433 is a prime number
BaseRepresentation
bin11010000111110101…
…00111001111010001
31100012101021022101001
431003322213033101
5212210212343213
610235342142001
71004351632615
oct150372471721
940171238331
1014024340433
115a474135a4
122874881901
131426681abc
14970811345
155713401dd
hex343ea73d1

14024340433 has 2 divisors, whose sum is σ = 14024340434. Its totient is φ = 14024340432.

The previous prime is 14024340427. The next prime is 14024340487. The reversal of 14024340433 is 33404342041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11553455169 + 2470885264 = 107487^2 + 49708^2 .

It is a cyclic number.

It is not a de Polignac number, because 14024340433 - 225 = 13990786001 is a prime.

It is a super-3 number, since 3×140243404333 (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (14024340493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7012170216 + 7012170217.

It is an arithmetic number, because the mean of its divisors is an integer number (7012170217).

Almost surely, 214024340433 is an apocalyptic number.

It is an amenable number.

14024340433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14024340433 is an equidigital number, since it uses as much as digits as its factorization.

14024340433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 28.

Adding to 14024340433 its reverse (33404342041), we get a palindrome (47428682474).

The spelling of 14024340433 in words is "fourteen billion, twenty-four million, three hundred forty thousand, four hundred thirty-three".