Base | Representation |
---|---|
bin | 10000101110000… |
… | …01111011010011 |
3 | 100202220200121002 |
4 | 20113001323103 |
5 | 241401124211 |
6 | 21530052215 |
7 | 3322101335 |
oct | 1027017323 |
9 | 322820532 |
10 | 140254931 |
11 | 72196673 |
12 | 3ab7a06b |
13 | 230993ab |
14 | 148ad455 |
15 | c4a703b |
hex | 85c1ed3 |
140254931 has 2 divisors, whose sum is σ = 140254932. Its totient is φ = 140254930.
The previous prime is 140254927. The next prime is 140254937. The reversal of 140254931 is 139452041.
140254931 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (139452041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 140254931 - 22 = 140254927 is a prime.
It is a super-2 number, since 2×1402549312 = 39342891339629522, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 140254894 and 140254903.
It is not a weakly prime, because it can be changed into another prime (140254937) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70127465 + 70127466.
It is an arithmetic number, because the mean of its divisors is an integer number (70127466).
Almost surely, 2140254931 is an apocalyptic number.
140254931 is a deficient number, since it is larger than the sum of its proper divisors (1).
140254931 is an equidigital number, since it uses as much as digits as its factorization.
140254931 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 29.
The square root of 140254931 is about 11842.9274674803. The cubic root of 140254931 is about 519.5643923402.
The spelling of 140254931 in words is "one hundred forty million, two hundred fifty-four thousand, nine hundred thirty-one".
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