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140264015113 is a prime number
BaseRepresentation
bin1000001010100001100…
…0110000010100001001
3111102001020111020101201
42002220120300110021
54244230041440423
6144234132344201
713063605312445
oct2025030602411
9442036436351
10140264015113
115453841a652
1223226175061
13102c44a0961
146b08715825
1539adec32ad
hex20a8630509

140264015113 has 2 divisors, whose sum is σ = 140264015114. Its totient is φ = 140264015112.

The previous prime is 140264015083. The next prime is 140264015149. The reversal of 140264015113 is 311510462041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 137828790009 + 2435225104 = 371253^2 + 49348^2 .

It is a cyclic number.

It is not a de Polignac number, because 140264015113 - 25 = 140264015081 is a prime.

It is not a weakly prime, because it can be changed into another prime (140264015183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70132007556 + 70132007557.

It is an arithmetic number, because the mean of its divisors is an integer number (70132007557).

Almost surely, 2140264015113 is an apocalyptic number.

It is an amenable number.

140264015113 is a deficient number, since it is larger than the sum of its proper divisors (1).

140264015113 is an equidigital number, since it uses as much as digits as its factorization.

140264015113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 140264015113 its reverse (311510462041), we get a palindrome (451774477154).

The spelling of 140264015113 in words is "one hundred forty billion, two hundred sixty-four million, fifteen thousand, one hundred thirteen".