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140310433 = 314526143
BaseRepresentation
bin10000101110011…
…11011110100001
3100210000111201201
420113033132201
5241404413213
621531201201
73322422214
oct1027173641
9323014651
10140310433
117222433a
123aba6201
13230b8733
14148c577b
15c4b86dd
hex85cf7a1

140310433 has 4 divisors (see below), whose sum is σ = 144836608. Its totient is φ = 135784260.

The previous prime is 140310427. The next prime is 140310473. The reversal of 140310433 is 334013041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140310433 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 140310433.

It is not an unprimeable number, because it can be changed into a prime (140310473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2263041 + ... + 2263102.

It is an arithmetic number, because the mean of its divisors is an integer number (36209152).

Almost surely, 2140310433 is an apocalyptic number.

It is an amenable number.

140310433 is a deficient number, since it is larger than the sum of its proper divisors (4526175).

140310433 is an equidigital number, since it uses as much as digits as its factorization.

140310433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4526174.

The product of its (nonzero) digits is 432, while the sum is 19.

The square root of 140310433 is about 11845.2704907908. The cubic root of 140310433 is about 519.6329177026.

Adding to 140310433 its reverse (334013041), we get a palindrome (474323474).

The spelling of 140310433 in words is "one hundred forty million, three hundred ten thousand, four hundred thirty-three".

Divisors: 1 31 4526143 140310433