Base | Representation |
---|---|
bin | 1100110000101101110000… |
… | …0111110100001111011011 |
3 | 1211200100121102200122210002 |
4 | 3030023130013310033123 |
5 | 3314341100343201433 |
6 | 45501440033443215 |
7 | 2645465440043231 |
oct | 314133407641733 |
9 | 54610542618702 |
10 | 14031056225243 |
11 | 451a5a04a5342 |
12 | 16a739041050b |
13 | 7aa17a0b0ca5 |
14 | 36716cc9c951 |
15 | 194ea76129e8 |
hex | cc2dc1f43db |
14031056225243 has 2 divisors, whose sum is σ = 14031056225244. Its totient is φ = 14031056225242.
The previous prime is 14031056225201. The next prime is 14031056225257. The reversal of 14031056225243 is 34252265013041.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14031056225243 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14031056225197 and 14031056225206.
It is not a weakly prime, because it can be changed into another prime (14031056225293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7015528112621 + 7015528112622.
It is an arithmetic number, because the mean of its divisors is an integer number (7015528112622).
Almost surely, 214031056225243 is an apocalyptic number.
14031056225243 is a deficient number, since it is larger than the sum of its proper divisors (1).
14031056225243 is an equidigital number, since it uses as much as digits as its factorization.
14031056225243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 38.
The spelling of 14031056225243 in words is "fourteen trillion, thirty-one billion, fifty-six million, two hundred twenty-five thousand, two hundred forty-three".
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