Base | Representation |
---|---|
bin | 1000001010101100110… |
… | …1010001000011110010 |
3 | 111102011112112100021211 |
4 | 2002223031101003302 |
5 | 4244324200211104 |
6 | 144242542510334 |
7 | 13065021445654 |
oct | 2025315210362 |
9 | 442145470254 |
10 | 140311335154 |
11 | 545620aa921 |
12 | 23239b953aa |
13 | 1030122b293 |
14 | 6b10b126d4 |
15 | 39b321de04 |
hex | 20ab3510f2 |
140311335154 has 4 divisors (see below), whose sum is σ = 210467002734. Its totient is φ = 70155667576.
The previous prime is 140311335149. The next prime is 140311335169. The reversal of 140311335154 is 451533113041.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 137971388025 + 2339947129 = 371445^2 + 48373^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35077833787 + ... + 35077833790.
Almost surely, 2140311335154 is an apocalyptic number.
140311335154 is a deficient number, since it is larger than the sum of its proper divisors (70155667580).
140311335154 is an equidigital number, since it uses as much as digits as its factorization.
140311335154 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70155667579.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 140311335154 its reverse (451533113041), we get a palindrome (591844448195).
The spelling of 140311335154 in words is "one hundred forty billion, three hundred eleven million, three hundred thirty-five thousand, one hundred fifty-four".
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