Base | Representation |
---|---|
bin | 1100110000101110110100… |
… | …1010111000001010010011 |
3 | 1211200101100100212201211011 |
4 | 3030023231022320022103 |
5 | 3314342142103143103 |
6 | 45501524252031351 |
7 | 2645505512115535 |
oct | 314135512701223 |
9 | 54611310781734 |
10 | 14031342240403 |
11 | 451a727997804 |
12 | 16a7450162557 |
13 | 7aa1c4423527 |
14 | 367198c71855 |
15 | 194ec27acd6d |
hex | cc2ed2b8293 |
14031342240403 has 4 divisors (see below), whose sum is σ = 14112448265088. Its totient is φ = 13950236215720.
The previous prime is 14031342240389. The next prime is 14031342240407. The reversal of 14031342240403 is 30404224313041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14031342240403 - 217 = 14031342109331 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14031342240407) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40553012083 + ... + 40553012428.
It is an arithmetic number, because the mean of its divisors is an integer number (3528112066272).
Almost surely, 214031342240403 is an apocalyptic number.
14031342240403 is a deficient number, since it is larger than the sum of its proper divisors (81106024685).
14031342240403 is an equidigital number, since it uses as much as digits as its factorization.
14031342240403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 81106024684.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 14031342240403 its reverse (30404224313041), we get a palindrome (44435566553444).
The spelling of 14031342240403 in words is "fourteen trillion, thirty-one billion, three hundred forty-two million, two hundred forty thousand, four hundred three".
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