1403134342121 has 4 divisors (see below), whose sum is σ = 1408469453952. Its totient is φ = 1397799230292.

The previous prime is 1403134342111. The next prime is 1403134342201. The reversal of 1403134342121 is 1212434313041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1403134342121 - 2¹⁴ = 1403134325737 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1403134342111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2667555521 + ... + 2667556046.

It is an arithmetic number, because the mean of its divisors is an integer number (352117363488).

Almost surely, 2^{1403134342121} is an apocalyptic number.

It is an amenable number.

1403134342121 is a deficient number, since it is larger than the sum of its proper divisors (5335111831).

1403134342121 is an equidigital number, since it uses as much as digits as its factorization.

1403134342121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5335111830.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1403134342121 its reverse (1212434313041), we get a palindrome (2615568655162).

The spelling of 1403134342121 in words is "one trillion, four hundred three billion, one hundred thirty-four million, three hundred forty-two thousand, one hundred twenty-one".