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14031410401 = 49332844397
BaseRepresentation
bin11010001000101011…
…00101010011100001
31100012212120111112201
431010111211103201
5212214020113101
610240153453201
71004466010021
oct150425452341
940185514481
1014031410401
115a50402348
122877111201
131427c88b08
14971731a81
15571c89e01
hex3445654e1

14031410401 has 4 divisors (see below), whose sum is σ = 14034259732. Its totient is φ = 14028561072.

The previous prime is 14031410387. The next prime is 14031410447. The reversal of 14031410401 is 10401413041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3911251600 + 10120158801 = 62540^2 + 100599^2 .

It is a cyclic number.

It is not a de Polignac number, because 14031410401 - 25 = 14031410369 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14031410101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1417266 + ... + 1427131.

It is an arithmetic number, because the mean of its divisors is an integer number (3508564933).

Almost surely, 214031410401 is an apocalyptic number.

It is an amenable number.

14031410401 is a deficient number, since it is larger than the sum of its proper divisors (2849331).

14031410401 is an equidigital number, since it uses as much as digits as its factorization.

14031410401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2849330.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 14031410401 its reverse (10401413041), we get a palindrome (24432823442).

The spelling of 14031410401 in words is "fourteen billion, thirty-one million, four hundred ten thousand, four hundred one".

Divisors: 1 4933 2844397 14031410401