14031412413001 has 4 divisors (see below), whose sum is σ = 14484038619904. Its totient is φ = 13578786206100.

The previous prime is 14031412412929. The next prime is 14031412413047. The reversal of 14031412413001 is 10031421413041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14031412413001 - 2¹⁵ = 14031412380233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14031412413301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 226313103405 + ... + 226313103466.

It is an arithmetic number, because the mean of its divisors is an integer number (3621009654976).

Almost surely, 2^{14031412413001} is an apocalyptic number.

It is an amenable number.

14031412413001 is a deficient number, since it is larger than the sum of its proper divisors (452626206903).

14031412413001 is an equidigital number, since it uses as much as digits as its factorization.

14031412413001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 452626206902.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14031412413001 its reverse (10031421413041), we get a palindrome (24062833826042).

The spelling of 14031412413001 in words is "fourteen trillion, thirty-one billion, four hundred twelve million, four hundred thirteen thousand, one".