14031413241113 has 2 divisors, whose sum is σ = 14031413241114. Its totient is φ = 14031413241112.

The previous prime is 14031413241103. The next prime is 14031413241121. The reversal of 14031413241113 is 31114231413041.

14031413241113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13704122840464 + 327290400649 = 3701908^2 + 572093^2 .

It is a cyclic number.

It is not a de Polignac number, because 14031413241113 - 2⁸ = 14031413240857 is a prime.

It is not a weakly prime, because it can be changed into another prime (14031413241103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7015706620556 + 7015706620557.

It is an arithmetic number, because the mean of its divisors is an integer number (7015706620557).

Almost surely, 2^{14031413241113} is an apocalyptic number.

It is an amenable number.

14031413241113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14031413241113 is an equidigital number, since it uses as much as digits as its factorization.

14031413241113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 14031413241113 its reverse (31114231413041), we get a palindrome (45145644654154).

The spelling of 14031413241113 in words is "fourteen trillion, thirty-one billion, four hundred thirteen million, two hundred forty-one thousand, one hundred thirteen".