140315112331 has 2 divisors, whose sum is σ = 140315112332. Its totient is φ = 140315112330.

The previous prime is 140315112307. The next prime is 140315112341. The reversal of 140315112331 is 133211513041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 140315112331 - 2⁵ = 140315112299 is a prime.

It is a super-2 number, since 2×140315112331² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140315112296 and 140315112305.

It is not a weakly prime, because it can be changed into another prime (140315112341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70157556165 + 70157556166.

It is an arithmetic number, because the mean of its divisors is an integer number (70157556166).

Almost surely, 2^140315112331 is an apocalyptic number.

140315112331 is a deficient number, since it is larger than the sum of its proper divisors (1).

140315112331 is an equidigital number, since it uses as much as digits as its factorization.

140315112331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 140315112331 its reverse (133211513041), we get a palindrome (273526625372).

The spelling of 140315112331 in words is "one hundred forty billion, three hundred fifteen million, one hundred twelve thousand, three hundred thirty-one".