Base | Representation |
---|---|
bin | 10100011010110101010… |
… | …000110001111000011011 |
3 | 11222010220110010122001111 |
4 | 110122311100301320123 |
5 | 140442223301210321 |
6 | 2552342114401151 |
7 | 203243420500552 |
oct | 24326520617033 |
9 | 4863813118044 |
10 | 1403200413211 |
11 | 4a1104063093 |
12 | 1a7b48b901b7 |
13 | a242398b7bc |
14 | 4bcb56a0d99 |
15 | 267790e05e1 |
hex | 146b5431e1b |
1403200413211 has 2 divisors, whose sum is σ = 1403200413212. Its totient is φ = 1403200413210.
The previous prime is 1403200413187. The next prime is 1403200413239. The reversal of 1403200413211 is 1123140023041.
It is a weak prime.
It is an emirp because it is prime and its reverse (1123140023041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1403200413211 - 221 = 1403198316059 is a prime.
It is a super-2 number, since 2×14032004132112 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1403207413211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701600206605 + 701600206606.
It is an arithmetic number, because the mean of its divisors is an integer number (701600206606).
Almost surely, 21403200413211 is an apocalyptic number.
1403200413211 is a deficient number, since it is larger than the sum of its proper divisors (1).
1403200413211 is an equidigital number, since it uses as much as digits as its factorization.
1403200413211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 1403200413211 its reverse (1123140023041), we get a palindrome (2526340436252).
The spelling of 1403200413211 in words is "one trillion, four hundred three billion, two hundred million, four hundred thirteen thousand, two hundred eleven".
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