Base | Representation |
---|---|
bin | 1000001010101110111… |
… | …0101111011101100001 |
3 | 111102012011001011201011 |
4 | 2002223232233131201 |
5 | 4244333422013213 |
6 | 144243454540521 |
7 | 13065156154606 |
oct | 2025356573541 |
9 | 442164034634 |
10 | 140320110433 |
11 | 54567053918 |
12 | 23240b07741 |
13 | 10302cb1559 |
14 | 6b11d586ad |
15 | 39b3da403d |
hex | 20abbaf761 |
140320110433 has 2 divisors, whose sum is σ = 140320110434. Its totient is φ = 140320110432.
The previous prime is 140320110421. The next prime is 140320110461. The reversal of 140320110433 is 334011023041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 140277964369 + 42146064 = 374537^2 + 6492^2 .
It is an emirp because it is prime and its reverse (334011023041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 140320110433 - 25 = 140320110401 is a prime.
It is not a weakly prime, because it can be changed into another prime (140320110473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70160055216 + 70160055217.
It is an arithmetic number, because the mean of its divisors is an integer number (70160055217).
Almost surely, 2140320110433 is an apocalyptic number.
It is an amenable number.
140320110433 is a deficient number, since it is larger than the sum of its proper divisors (1).
140320110433 is an equidigital number, since it uses as much as digits as its factorization.
140320110433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 140320110433 its reverse (334011023041), we get a palindrome (474331133474).
The spelling of 140320110433 in words is "one hundred forty billion, three hundred twenty million, one hundred ten thousand, four hundred thirty-three".
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