14032015513441 has 2 divisors, whose sum is σ = 14032015513442. Its totient is φ = 14032015513440.

The previous prime is 14032015513363. The next prime is 14032015513457. The reversal of 14032015513441 is 14431551023041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11562312115600 + 2469703397841 = 3400340^2 + 1571529^2 .

It is a cyclic number.

It is not a de Polignac number, because 14032015513441 - 2¹⁷ = 14032015382369 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14032015513397 and 14032015513406.

It is not a weakly prime, because it can be changed into another prime (14032015510441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7016007756720 + 7016007756721.

It is an arithmetic number, because the mean of its divisors is an integer number (7016007756721).

Almost surely, 2^{14032015513441} is an apocalyptic number.

It is an amenable number.

14032015513441 is a deficient number, since it is larger than the sum of its proper divisors (1).

14032015513441 is an equidigital number, since it uses as much as digits as its factorization.

14032015513441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 14032015513441 its reverse (14431551023041), we get a palindrome (28463566536482).

The spelling of 14032015513441 in words is "fourteen trillion, thirty-two billion, fifteen million, five hundred thirteen thousand, four hundred forty-one".