14032224110131 has 2 divisors, whose sum is σ = 14032224110132. Its totient is φ = 14032224110130.

The previous prime is 14032224110063. The next prime is 14032224110147. The reversal of 14032224110131 is 13101142223041.

14032224110131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14032224110131 - 2¹³ = 14032224101939 is a prime.

It is a super-2 number, since 2×14032224110131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14032224110096 and 14032224110105.

It is not a weakly prime, because it can be changed into another prime (14032224111131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7016112055065 + 7016112055066.

It is an arithmetic number, because the mean of its divisors is an integer number (7016112055066).

Almost surely, 2^{14032224110131} is an apocalyptic number.

14032224110131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14032224110131 is an equidigital number, since it uses as much as digits as its factorization.

14032224110131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14032224110131 its reverse (13101142223041), we get a palindrome (27133366333172).

The spelling of 14032224110131 in words is "fourteen trillion, thirty-two billion, two hundred twenty-four million, one hundred ten thousand, one hundred thirty-one".