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140322550153 = 515032724551
BaseRepresentation
bin1000001010101111100…
…0000011000110001001
3111102012022122010101011
42002223320003012021
54244340033101103
6144244023123521
713065215665522
oct2025370030611
9442168563334
10140322550153
115456846a915
12232418a35a1
1310303656b86
146b123d1849
1539b41d6d6d
hex20abe03189

140322550153 has 4 divisors (see below), whose sum is σ = 140325326208. Its totient is φ = 140319774100.

The previous prime is 140322550139. The next prime is 140322550217. The reversal of 140322550153 is 351055223041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140322550153 - 233 = 131732615561 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140322550853) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1310773 + ... + 1413778.

It is an arithmetic number, because the mean of its divisors is an integer number (35081331552).

Almost surely, 2140322550153 is an apocalyptic number.

It is an amenable number.

140322550153 is a deficient number, since it is larger than the sum of its proper divisors (2776055).

140322550153 is an equidigital number, since it uses as much as digits as its factorization.

140322550153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2776054.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 140322550153 its reverse (351055223041), we get a palindrome (491377773194).

The spelling of 140322550153 in words is "one hundred forty billion, three hundred twenty-two million, five hundred fifty thousand, one hundred fifty-three".

Divisors: 1 51503 2724551 140322550153