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14032320192947 = 72004617170421
BaseRepresentation
bin1100110000110010011101…
…1101011110000110110011
31211200110212112001212111202
43030030213131132012303
53314401142432133242
645502205305001415
72645541655432250
oct314144735360663
954613775055452
1014032320192947
114520089a21a51
1216a768378326b
137aa31bc11384
1436724cac0427
1519502d586932
hexcc32775e1b3

14032320192947 has 4 divisors (see below), whose sum is σ = 16036937363376. Its totient is φ = 12027703022520.

The previous prime is 14032320192941. The next prime is 14032320193061. The reversal of 14032320192947 is 74929102323041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14032320192947 - 218 = 14032319930803 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14032320192941) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1002308585204 + ... + 1002308585217.

It is an arithmetic number, because the mean of its divisors is an integer number (4009234340844).

Almost surely, 214032320192947 is an apocalyptic number.

14032320192947 is a deficient number, since it is larger than the sum of its proper divisors (2004617170429).

14032320192947 is an equidigital number, since it uses as much as digits as its factorization.

14032320192947 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2004617170428.

The product of its (nonzero) digits is 653184, while the sum is 47.

The spelling of 14032320192947 in words is "fourteen trillion, thirty-two billion, three hundred twenty million, one hundred ninety-two thousand, nine hundred forty-seven".

Divisors: 1 7 2004617170421 14032320192947