Base | Representation |
---|---|
bin | 1100110000110010011110… |
… | …0101100110001001100010 |
3 | 1211200110212200002002110011 |
4 | 3030030213211212021202 |
5 | 3314401144003314132 |
6 | 45502205422355134 |
7 | 2645542012513402 |
oct | 314144745461142 |
9 | 54613780062404 |
10 | 14032322323042 |
11 | 4520090147361 |
12 | 16a768442baaa |
13 | 7aa31c4a8a9a |
14 | 36724d0b6802 |
15 | 19502d857b47 |
hex | cc327966262 |
14032322323042 has 8 divisors (see below), whose sum is σ = 21302079671376. Its totient is φ = 6931629099252.
The previous prime is 14032322323027. The next prime is 14032322323051. The reversal of 14032322323042 is 24032322323041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 14032322322995 and 14032322323013.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42266030928 + ... + 42266031259.
It is an arithmetic number, because the mean of its divisors is an integer number (2662759958922).
Almost surely, 214032322323042 is an apocalyptic number.
14032322323042 is a deficient number, since it is larger than the sum of its proper divisors (7269757348334).
14032322323042 is an equidigital number, since it uses as much as digits as its factorization.
14032322323042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 84532062272.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 14032322323042 its reverse (24032322323041), we get a palindrome (38064644646083).
Subtracting 14032322323042 from its reverse (24032322323041), we obtain a palindrome (9999999999999).
The spelling of 14032322323042 in words is "fourteen trillion, thirty-two billion, three hundred twenty-two million, three hundred twenty-three thousand, forty-two".
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