Base | Representation |
---|---|
bin | 11010001000110010… |
… | …10111101100100001 |
3 | 1100012221102221110021 |
4 | 31010121113230201 |
5 | 212214243400413 |
6 | 10240231033441 |
7 | 1004510313412 |
oct | 150431275441 |
9 | 40187387407 |
10 | 14032403233 |
11 | 5a50a20272 |
12 | 287750b881 |
13 | 14282459a4 |
14 | 97190d809 |
15 | 571dd418d |
hex | 344657b21 |
14032403233 has 2 divisors, whose sum is σ = 14032403234. Its totient is φ = 14032403232.
The previous prime is 14032403219. The next prime is 14032403243. The reversal of 14032403233 is 33230423041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10906251489 + 3126151744 = 104433^2 + 55912^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14032403233 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14032403198 and 14032403207.
It is not a weakly prime, because it can be changed into another prime (14032403243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7016201616 + 7016201617.
It is an arithmetic number, because the mean of its divisors is an integer number (7016201617).
Almost surely, 214032403233 is an apocalyptic number.
It is an amenable number.
14032403233 is a deficient number, since it is larger than the sum of its proper divisors (1).
14032403233 is an equidigital number, since it uses as much as digits as its factorization.
14032403233 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 14032403233 its reverse (33230423041), we get a palindrome (47262826274).
The spelling of 14032403233 in words is "fourteen billion, thirty-two million, four hundred three thousand, two hundred thirty-three".
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