Base | Representation |
---|---|
bin | 1100110000110010110011… |
… | …1100100001110010001001 |
3 | 1211200111002221020100122121 |
4 | 3030030230330201302021 |
5 | 3314401340012024203 |
6 | 45502222353251241 |
7 | 2645544153601306 |
oct | 314145474416211 |
9 | 54614087210577 |
10 | 14032412220553 |
11 | 4520126968721 |
12 | 16a76aa563b21 |
13 | 7aa334cc318c |
14 | 36725add80ad |
15 | 1950366b40bd |
hex | cc32cf21c89 |
14032412220553 has 8 divisors (see below), whose sum is σ = 14125881246048. Its totient is φ = 13939033202784.
The previous prime is 14032412220551. The next prime is 14032412220709. The reversal of 14032412220553 is 35502221423041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14032412220553 - 21 = 14032412220551 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14032412220551) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22189075 + ... + 22812712.
It is an arithmetic number, because the mean of its divisors is an integer number (1765735155756).
Almost surely, 214032412220553 is an apocalyptic number.
It is an amenable number.
14032412220553 is a deficient number, since it is larger than the sum of its proper divisors (93469025495).
14032412220553 is a wasteful number, since it uses less digits than its factorization.
14032412220553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45003863.
The product of its (nonzero) digits is 57600, while the sum is 34.
Adding to 14032412220553 its reverse (35502221423041), we get a palindrome (49534633643594).
The spelling of 14032412220553 in words is "fourteen trillion, thirty-two billion, four hundred twelve million, two hundred twenty thousand, five hundred fifty-three".
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