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140325053323 = 71314091094417
BaseRepresentation
bin1000001010110000000…
…1100110001110001011
3111102012111100022002011
42002230001212032023
54244341203201243
6144244152520351
713065246162430
oct2025401461613
9442174308064
10140325053323
115456991a554
12232426b00b7
1310304022340
146b12883b87
1539b452d89d
hex20ac06638b

140325053323 has 16 divisors (see below), whose sum is σ = 172830490560. Its totient is φ = 110947516416.

The previous prime is 140325053321. The next prime is 140325053353. The reversal of 140325053323 is 323350523041.

It is a cyclic number.

It is not a de Polignac number, because 140325053323 - 21 = 140325053321 is a prime.

It is a super-2 number, since 2×1403250533232 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (140325053321) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 418990 + ... + 675427.

It is an arithmetic number, because the mean of its divisors is an integer number (10801905660).

Almost surely, 2140325053323 is an apocalyptic number.

140325053323 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

140325053323 is a deficient number, since it is larger than the sum of its proper divisors (32505437237).

140325053323 is a wasteful number, since it uses less digits than its factorization.

140325053323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1095846.

The product of its (nonzero) digits is 32400, while the sum is 31.

Adding to 140325053323 its reverse (323350523041), we get a palindrome (463675576364).

The spelling of 140325053323 in words is "one hundred forty billion, three hundred twenty-five million, fifty-three thousand, three hundred twenty-three".

Divisors: 1 7 13 91 1409 9863 18317 128219 1094417 7660919 14227421 99591947 1542033553 10794234871 20046436189 140325053323