Base | Representation |
---|---|
bin | 1000001010110000000… |
… | …1100110001110001011 |
3 | 111102012111100022002011 |
4 | 2002230001212032023 |
5 | 4244341203201243 |
6 | 144244152520351 |
7 | 13065246162430 |
oct | 2025401461613 |
9 | 442174308064 |
10 | 140325053323 |
11 | 5456991a554 |
12 | 232426b00b7 |
13 | 10304022340 |
14 | 6b12883b87 |
15 | 39b452d89d |
hex | 20ac06638b |
140325053323 has 16 divisors (see below), whose sum is σ = 172830490560. Its totient is φ = 110947516416.
The previous prime is 140325053321. The next prime is 140325053353. The reversal of 140325053323 is 323350523041.
It is a cyclic number.
It is not a de Polignac number, because 140325053323 - 21 = 140325053321 is a prime.
It is a super-2 number, since 2×1403250533232 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (140325053321) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 418990 + ... + 675427.
It is an arithmetic number, because the mean of its divisors is an integer number (10801905660).
Almost surely, 2140325053323 is an apocalyptic number.
140325053323 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
140325053323 is a deficient number, since it is larger than the sum of its proper divisors (32505437237).
140325053323 is a wasteful number, since it uses less digits than its factorization.
140325053323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1095846.
The product of its (nonzero) digits is 32400, while the sum is 31.
Adding to 140325053323 its reverse (323350523041), we get a palindrome (463675576364).
The spelling of 140325053323 in words is "one hundred forty billion, three hundred twenty-five million, fifty-three thousand, three hundred twenty-three".
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