140330344131121 has 4 divisors (see below), whose sum is σ = 141170645593152. Its totient is φ = 139490042669092.

The previous prime is 140330344131119. The next prime is 140330344131181. The reversal of 140330344131121 is 121131443033041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140330344131121 - 2¹ = 140330344131119 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140330344131181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 420150730765 + ... + 420150731098.

It is an arithmetic number, because the mean of its divisors is an integer number (35292661398288).

Almost surely, 2^{140330344131121} is an apocalyptic number.

It is an amenable number.

140330344131121 is a deficient number, since it is larger than the sum of its proper divisors (840301462031).

140330344131121 is an equidigital number, since it uses as much as digits as its factorization.

140330344131121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 840301462030.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 140330344131121 its reverse (121131443033041), we get a palindrome (261461787164162).

The spelling of 140330344131121 in words is "one hundred forty trillion, three hundred thirty billion, three hundred forty-four million, one hundred thirty-one thousand, one hundred twenty-one".