Base | Representation |
---|---|
bin | 1000001010110001100… |
… | …1011011011001011001 |
3 | 111102012221002200111220 |
4 | 2002230121123121121 |
5 | 4244344303103231 |
6 | 144244534442253 |
7 | 13065353241543 |
oct | 2025431333131 |
9 | 442187080456 |
10 | 140331300441 |
11 | 545723a7062 |
12 | 23244803389 |
13 | 103053cb967 |
14 | 6b1362c693 |
15 | 39b4d64896 |
hex | 20ac65b659 |
140331300441 has 4 divisors (see below), whose sum is σ = 187108400592. Its totient is φ = 93554200292.
The previous prime is 140331300337. The next prime is 140331300451. The reversal of 140331300441 is 144003133041.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 144003133041 = 3 ⋅48001044347.
It is a cyclic number.
It is not a de Polignac number, because 140331300441 - 225 = 140297746009 is a prime.
It is not an unprimeable number, because it can be changed into a prime (140331300451) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23388550071 + ... + 23388550076.
It is an arithmetic number, because the mean of its divisors is an integer number (46777100148).
Almost surely, 2140331300441 is an apocalyptic number.
It is an amenable number.
140331300441 is a deficient number, since it is larger than the sum of its proper divisors (46777100151).
140331300441 is an equidigital number, since it uses as much as digits as its factorization.
140331300441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46777100150.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 140331300441 its reverse (144003133041), we get a palindrome (284334433482).
The spelling of 140331300441 in words is "one hundred forty billion, three hundred thirty-one million, three hundred thousand, four hundred forty-one".
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