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14033341121411 = 126619711083063
BaseRepresentation
bin1100110000110110010001…
…0100000000001110000011
31211200120111200010102002002
43030031210110000032003
53314410240311341121
645502454455014215
72645606163250133
oct314154424001603
954616450112062
1014033341121411
11452056323a687
1216a790966a36b
137aa452598461
14367308518ac3
1519508ceede0b
hexcc364500383

14033341121411 has 4 divisors (see below), whose sum is σ = 14033353470672. Its totient is φ = 14033328772152.

The previous prime is 14033341121329. The next prime is 14033341121419. The reversal of 14033341121411 is 11412114333041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14033341121411 - 222 = 14033336927107 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14033341121419) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4275335 + ... + 6807728.

It is an arithmetic number, because the mean of its divisors is an integer number (3508338367668).

Almost surely, 214033341121411 is an apocalyptic number.

14033341121411 is a deficient number, since it is larger than the sum of its proper divisors (12349261).

14033341121411 is a wasteful number, since it uses less digits than its factorization.

14033341121411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12349260.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 14033341121411 its reverse (11412114333041), we get a palindrome (25445455454452).

The spelling of 14033341121411 in words is "fourteen trillion, thirty-three billion, three hundred forty-one million, one hundred twenty-one thousand, four hundred eleven".

Divisors: 1 1266197 11083063 14033341121411